What is the sum of 3 6/9 + 6 1/3 + 9 5/9?

What is the sum of 3 6/9 + 6 1/3 + 9 5/9?

• A. 19 5/9
• B. 18 1/3
• C. 15 2/9
• D. 20

Answer: (A)

To find the sum of the mixed numbers \(3 \frac{6}{9}\), \(6 \frac{1}{3}\), and \(9 \frac{5}{9}\), it’s important to convert each mixed number into an improper fraction first. 1. For \(3 \frac{6}{9}\): - Convert to an improper fraction: \[ (3 \times 9 + 6) / 9 = (27 + 6) / 9 = 33/9 \] 2. For \(6 \frac{1}{3}\): - Convert to an improper fraction: \[ (6 \times 3 + 1) / 3 = (18 + 1) / 3 = 19/3 \] - To add it to the other fractions, convert \(19/3\) to a fraction with a denominator of 9: \[ 19/3 \times 3/3 = 57/9 \] 3. For \(9 \frac{5}{9}\): - Convert to an improper fraction: \[ (9 \times

To find the sum of the mixed numbers (3 \frac{6}{9}), (6 \frac{1}{3}), and (9 \frac{5}{9}), it’s important to convert each mixed number into an improper fraction first.

1. For (3 \frac{6}{9}):

• Convert to an improper fraction:

[

(3 \times 9 + 6) / 9 = (27 + 6) / 9 = 33/9

]

2. For (6 \frac{1}{3}):

• Convert to an improper fraction:

[

(6 \times 3 + 1) / 3 = (18 + 1) / 3 = 19/3

]

• To add it to the other fractions, convert (19/3) to a fraction with a denominator of 9:

[

19/3 \times 3/3 = 57/9

]

3. For (9 \frac{5}{9}):

• Convert to an improper fraction:

[

(9 \times